3b^2-5b=18

Solution for 3b^2-5b=18 equation:

3b^2-5b=18

We move all terms to the left:

3b^2-5b-(18)=0

a = 3; b = -5; c = -18;
Δ = b2-4ac
Δ = -52-4·3·(-18)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{241}}{2*3}=\frac{5-\sqrt{241}}{6}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{241}}{2*3}=\frac{5+\sqrt{241}}{6}
$